Remember the definitions.
Molarity = # mols/L.
and # mols = g/molar mass.
How many moles CaCl2 do you have in 11.1 g CaCl2. That will be 11.1 g CaCl2/molar mass CaCl2.
Then #mols = M x L.
You have M and you have mols, calculate L.
The procedure suggested by DrBob 222 will give the correct answer to the question. However, the wording of the question itself could be improved. It might be: "Calculate the total volume of solution (water + CaCl2) when a 0.0250 M CaCl2 solution is prepared by dissolving 1.11 g of CaCl2 in a small volume of water and diluting to the calculated volume.".
The amount of water added cannot be calculated with complete precision since the volume of the solution includes both, water and calcium chloride.
Calculate the solubility of Cacl2 in g/L based on the experiement. Given 650g of CaCl2 added to 1.0L and allowed to dissolve as much as possible. While the remaining solid CaCl2 is filtered out of the solution and found to have a
How mush CaCl2, in grams, is needed to make 2.0 L of a 3.5M solution? g CaCl2 = (2.0L) *( 3.5 mol Cl-/1L) * (1mol CaCl2/ 2mol Cl-) *( 110.98 g CaCl2/ 1 mol CaCl2) = 5.549 g CaCl2 i don't think i did any of this right