Physics

Suppose the surface (radius = r) of a cylindrical space station is rotating at 29.1 m/s to provide artificial gravity. What must be the value of r for the astronauts to weigh 1/3 of their earth weight?
Don't know how to start please help.

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  1. Got it: reasoning and solution..
    the normal force exerted by the wall on each astronaut is the centripetal force needed to keep him in the circular path
    so, Fc=mv^2/r. rearranging and letting Fc=(1/3)mg yields
    r=3v^2/g= 3(29.1m/s)^2/(9.8m/s^2)=259m

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  2. hell yeah s thats what im talking about buddy. if you disliked this u probably didnt plug ur numbers in correctly

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