1) A 10 kg lead brick rests on a wooden table. if a force of 46N is required to slide the brick across the table at a constant velocity, what is the coefficient of friction?

2) A horizontal force of 100N is applied to a 200 kg refrigerator sitting on a horizontal surface. the refrigerator remains at rest. what is the value of the frictional force acting on the refrigerator? what will be the value of the frictional force on the refrigerator if the horizontal push is removed?

Show work please so I can see how these type of questions are solved.

Thank you so much!

1. Fb = m*g = 10 *9.8 = 98 N. = ForceFb of brick.

Fap-Fk = m*a
46 - Fk = m*0 = 0
Fk = 46 N. = Force of kinetic friction.

u = Fk/Fb = 46/98 = 0.469.

1) To find the coefficient of friction, we can use the formula:

Frictional force (F) = coefficient of friction (μ) × Normal force (N)

Given that the force required to slide the brick is 46N and the weight of the brick is 10 kg, we know that the normal force is equal to the weight of the brick:

Normal force (N) = mass (m) × acceleration due to gravity (g)
Normal force (N) = 10 kg × 9.8 m/s^2
Normal force (N) = 98 N

Now we can substitute the values into the formula:

46 N = μ × 98 N

To solve for μ, divide both sides of the equation by 98 N:

46 N / 98 N = μ
μ = 0.47

Therefore, the coefficient of friction is 0.47.

2) The frictional force acting on the refrigerator can be found using the same formula:

Frictional force (F) = μ × Normal force (N)

Given that the force applied is 100N and the mass of the refrigerator is 200 kg:

Normal force (N) = mass (m) × acceleration due to gravity (g)
Normal force (N) = 200 kg × 9.8 m/s^2
Normal force (N) = 1960 N

Now we can substitute the values into the formula:

Frictional force (F) = μ × Normal force (N)
Frictional force (F) = μ × 1960 N

To find the value of the frictional force, we need to know the coefficient of friction (μ). Without this information, we cannot determine the exact value of the frictional force.

However, if we remove the horizontal push, the frictional force will oppose the motion and try to bring the refrigerator to rest. In this case, if the refrigerator remains at rest, the frictional force will be equal to the applied force, which is 100N.

To solve these types of questions, we need to understand the concept of friction and the relationship with the normal force and the coefficient of friction.

1) To find the coefficient of friction, we need to use the equation:

μ = F_friction / F_normal

Where:
- μ is the coefficient of friction
- F_friction is the force of friction
- F_normal is the normal force

In this case, the normal force is the weight of the brick, which is equal to its mass multiplied by the acceleration due to gravity (g = 9.8 m/s²):

F_normal = m * g

Given:
- Mass of the brick (m) = 10 kg
- Force to slide the brick (F_friction) = 46 N

First, let's calculate the normal force:

F_normal = m * g
= 10 kg * 9.8 m/s²
= 98 N

Now, we can calculate the coefficient of friction:

μ = F_friction / F_normal
= 46 N / 98 N
≈ 0.469

Therefore, the coefficient of friction is approximately 0.469.

2) To find the value of the frictional force, we need to use the same equation as before:

F_friction = μ * F_normal

Given:
- Applied horizontal force (F_applied) = 100 N
- Mass of the refrigerator (m) = 200 kg

First, let's calculate the normal force. In this case, since the refrigerator is at rest, the normal force is equal in magnitude and opposite in direction to the applied force:

F_normal = F_applied = 100 N

Now, let's calculate the frictional force:

F_friction = μ * F_normal

a) When the horizontal push is applied:
- μ (coefficient of friction) is not given, so we cannot determine the exact value of the frictional force.

b) When the horizontal push is removed:
In this case, the refrigerator is at rest, so there is no external force acting on it. Thus, the frictional force should be equal in magnitude and opposite in direction to the normal force:

F_friction = -F_normal = -100 N

Therefore, when the horizontal push is removed, the value of the frictional force on the refrigerator is -100 N (opposite direction).