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Find three consecutive positive even integers such that four times the first decreased by the second is 12 more than twice the third.

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  1. n-2, n, n+2

    4(n-2) - n = 12 + 2(n+2)

    4 n - 8 - n - 12 - 2n - 4 = 0

    n - 24 = 0

    n = 24

    22 , 24, 26

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