physics

a ball is thrown straight up with a speed of 8.0 m/s from a third-floor window located 13.0 m above ground. Calculate the maximum height, measured from the ground, of the ball; calculate the ball's velocity when it reaches the ground, and calculate the total time it takes the ball to reach the ground.

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asked by Arleen
  1. a. ho + (V-Vo^2)/2g=13 + (0-(8^2)/-19.6 = 16.3 m. Above gnd.

    b. V^2 = Vo^2 + 2g*h
    Vo = 0 m/s, 2g = 19.6 m/s^2, h = 16.3 m.
    Calculate V.

    c. V = Vo + g*Tr = 0.
    Tr = -Vo/g = -8/-9.8 = 0.82 s=Rise time.

    h = 0.5g*t^2 = 16.3 m.
    4.9t^2 = 16.3
    t^2 = 3.33
    Tf = 1.82 s. = Fall time.

    Tr+Tf = 0.82 + 1.82 = 2.64 s. = Total
    time to reach gnd.

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    posted by Henry

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