Physics

A 60.0 kg person rides in elevator while standing on a scale. The elevator has an acceleration 2.00 m/s^2 upward. What is the reading on the scale?

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  1. 469

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  2. m=60.0
    a=2.00
    FN-mg=ma
    FN=ma + mg
    FN=m(a+g)
    FN=60(2.00+9.8)
    Answer 708N

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