Physics

A block is released from rest at the top of an inclined plane. The height of the plane is 5.00 m and it makes an angle of 30.0 degrees with the horizontal . The coefficient of kinetic friction between block and surface is 0.200. What is the speed of the block (in m/s) when it reaches the bottom of the incline?

asked by Fernando
  1. Horizontal direction :
    IF angle is measured from y axis (vertical line) -> a(horizontal) = Fsin(32)/m
    IF angle is measured from horizontal -> a(horizontal) = Fcos(32)/m

    Vertical direction:
    [ here positive a means acceleration down, negative a means up]
    IF angle is measured from vertical:
    If force is down -> a(vertical) = (Fcos(32) + mg)/m
    if force is up -> a(vertical) = (Fcos(32) - mg)/m

    If angle is measured from horizontal
    force is down -> a = (Fsin(32) + mg)/m
    force is up -> F = (Fsin(32) - mg)/m

    Then magnitude of acceleration = SQRT[acceleration(horizontal) ^ 2 + acceleration(vertical) ^ 2]

    posted by Matt

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