physics

Three forces act on a moving object. One force has a magnitude of 62.6 N and is directed due north. Another has a magnitude of 45.9 N and is directed due west. What must be (a) the magnitude and (b) the direction of the third force, such that the object continues to move with a constant velocity? Express your answer as a positive angle south of east.

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  1. Fn = 62.6
    Fw = 45.9
    |F| = sqrt (62.6^2+45.9^2) = 77.6
    angle north of west = tan^-1 (62.6/45.9)
    = 53.8 degrees
    so to cancel that
    77.6 at 53.8 south of east

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