What is the product of the oxidation of methanol? I'm not sure if it's formaldehyde? And would the product have water for an oxidizatiation
https://www.google.com/search?client=safari&rls=en&q=product+of+the+oxidation+of+methanol&ie=UTF-8&oe=UTF-8&gws_rd=ssl
In the future, you can find the information you desire more quickly, if you use appropriate key words to do your own search. Also see http://hanlib.sou.edu/searchtools/.
The product of the oxidation of methanol is indeed formaldehyde. Methanol (CH3OH) can be oxidized by various oxidizing agents such as air, oxygen, or certain reagents like chromic acid (H2CrO4) to produce formaldehyde (CH2O).
To determine the product of the oxidation reaction, you can follow these steps:
1. Write down the balanced equation: Methanol + Oxygen → Formaldehyde + Water
2. Identify the oxidation state of carbon in methanol. In methanol, carbon has an oxidation state of -II.
3. Determine the changes in the oxidation states during the oxidation process. In this case, carbon goes from -II in methanol to 0 in formaldehyde, indicating an oxidation process.
4. Balancing the equation: Since oxygen is the oxidizing agent, it will be reduced to form water (H2O). Combining these observations, the balanced equation becomes:
2CH3OH + O2 → 2CH2O + 2H2O
So, in summary, the product of the oxidation of methanol is formaldehyde (CH2O), and water (H2O) is also formed as a result of the oxidation.