Study the following codeC = A * B + 7 mod 3
If A > C then Display “A has a higher value that C” B = A – C Else Display “A is equal to or less than C”B = C – AEndifDisplay “the value of B is now “, BDisplay “the value of C is now”, C
What would be displayed if the code is executed and the following values apply?A = 5 and B = 7 ONLY type in the two values
To determine what would be displayed if the code is executed with A = 5 and B = 7, we can step through the code and compute the values of C and B one by one.
Given:
A = 5
B = 7
First, we calculate the value of C:
C = A * B + 7 mod 3
C = 5 * 7 + 7 mod 3
C = 35 + 7 mod 3
C = 42 mod 3
C = 0 (42 divided by 3 leaves a remainder of 0)
Next, we compare A and C:
If A > C, then display "A has a higher value than C".
Since A is not greater than C (5 is not greater than 0), this condition is not met.
Therefore, we move to the else clause and set:
B = C - A
B = 0 - 5
B = -5
Finally, we display the values of B and C:
Display "The value of B is now ", B
Output: "The value of B is now -5"
Display "The value of C is now ", C
Output: "The value of C is now 0"
So, if the code is executed with A = 5 and B = 7, the output would be:
"The value of B is now -5" and "The value of C is now 0".