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A volleyball player spikes the ball from a height of 2.44 meters. Assume that the path of the ball is a straight line. To the nearest degree, what is the maximum angle, θ, at which the ball can be hit and land within the court?

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  1. You have to know the size of the court. Assuming the spike is driven parallel to the side lines, then if the distance to the far line is x, and assuming you want the angle from the vertical (otherwise you'd be asking for the minimum angle), then

    x/2.44 = tan θ

    See how important it is to completely specify the parameters of the problem? I may have assumed several things which were not correct. You can, of course, correct them and review your basic trig functions to complete the solution.

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