A solution contains 5.6g of solute in 16 cm cubed of water. When the solution is cooled, crystals begin to appear at 11 degrees celsius. What is the solubility of the solute at 11 degrees celsius?
So at 11 C the solubility is 5.6g/16cc. Convert that to g/100 cc and you have
5.6 x 100/16 = ? g/100
To find the solubility of the solute at 11 degrees Celsius, we need to determine how much solute is dissolved in a given amount of solvent (water) at this temperature.
Here's how you can calculate it:
1. Convert the volume of water from cubic centimeters (cm³) to milliliters (mL) since both are equivalent. Therefore, 16 cm³ = 16 mL.
2. Calculate the concentration of the solute in the solution. Concentration is defined as the amount of solute per unit volume of the solution. It is commonly expressed in grams per milliliter (g/mL) or grams per centimeter cubed (g/cm³). In this case, we have 5.6 grams of solute in 16 mL of water.
Concentration = mass of solute / volume of solvent
Concentration = 5.6 g / 16 mL
3. Determine the solubility of the solute at 11 degrees Celsius. Solubility refers to the maximum amount of solute that can be dissolved in a given amount of solvent at a specific temperature. In this case, cooling the solution has caused some of the solute to come out of solution as crystals.
Therefore, the solubility of the solute at 11 degrees Celsius is equal to the concentration of the solute in the cooled solution.
So, the solubility of the solute at 11 degrees Celsius is 5.6 g / 16 mL, or approximately 0.35 g/mL.