If a sample of silver carbonate contains 1.75 grams of silver [Ag] atoms, calculate the mass (in grams) it contains of oxygen atoms [O].
To calculate the mass of oxygen atoms in the sample of silver carbonate, we need to first determine the composition of silver carbonate.
The formula for silver carbonate is Ag2CO3, which means it contains two silver ions (Ag+) and one carbonate ion (CO3^2-). To find the mass of oxygen atoms, we need to consider the molar ratio between oxygen and silver carbonate.
According to the formula Ag2CO3, there is one atom of carbon, three atoms of oxygen, and two atoms of silver. Therefore, the molar ratio of oxygen to silver carbonate is 3:1.
To calculate the mass of oxygen atoms in the sample, we can use the following steps:
Step 1: Calculate the molar mass of silver carbonate (Ag2CO3):
- The atomic mass of silver (Ag) is 107.87 g/mol.
- The atomic mass of carbon (C) is 12.01 g/mol.
- The atomic mass of oxygen (O) is 16.00 g/mol.
Molar mass of Ag2CO3 = (2 × atomic mass of Ag) + (1 × atomic mass of C) + (3 × atomic mass of O)
= (2 × 107.87 g/mol) + (12.01 g/mol) + (3 × 16.00 g/mol)
Step 2: Calculate the number of moles of silver atoms in the sample:
- Given mass of silver atoms (Ag) = 1.75 g
- Atomic mass of silver (Ag) = 107.87 g/mol
Number of moles of Ag atoms = mass of Ag atoms / atomic mass of Ag
= 1.75 g / 107.87 g/mol
Step 3: Calculate the number of moles of oxygen atoms in the sample:
- By using the molar ratio between oxygen and silver carbonate (3 moles of O : 1 mole of Ag2CO3), we can infer that the number of moles of oxygen atoms is three times the number of moles of silver carbonate.
Number of moles of O atoms = 3 × number of moles of Ag2CO3
Step 4: Calculate the mass of oxygen atoms in the sample:
- Using the molar mass of oxygen (O) and the number of moles of O atoms calculated in the previous step, we can calculate the mass of oxygen atoms in grams.
Mass of O atoms = number of moles of O atoms × molar mass of O
By following these steps, we can calculate the mass of oxygen atoms in the sample of silver carbonate.
Silver carbonate is Ag2CO3. I've rounded here and there and estimated so you must look up atomic masses and redo the math to obtain a more accurate anwer.
1.75 g Ag/108 = approx 0.016 mols Ag atoms.
1/2 that or 0.008 = mols Ag2CO3 molecules.
Then 3x that = mols oxygen since there are 3 atoms O per 1 molecule Ag2CO3.
Then convert mols oxygen to grams. g mols x molar mass