How much energy must you use to raise the temperature of 100 grams of water from 60 degrees Celsius to 70 degrees Celsius? show you calculations. I am confused on how to use formulas.
q = mass H2O x specific heat H2O x (Tfinal-Tinitial)
q = 100g x 4.184 J/g*C x (80C-60C)
q = ?
To calculate the amount of energy required to raise the temperature of a substance, we can use the formula:
Q = m * c * ∆T
Where:
- Q is the energy (in joules) required or released
- m is the mass of the substance (in grams)
- c is the specific heat capacity of the substance (in joules per gram per degree Celsius)
- ∆T is the change in temperature (in degrees Celsius)
For water, the specific heat capacity is approximately 4.18 joules per gram per degree Celsius.
Now, let's calculate the energy required to raise the temperature of 100 grams of water from 60 degrees Celsius to 70 degrees Celsius:
Step 1: Convert the temperature change to ∆T.
∆T = (final temperature) - (initial temperature)
∆T = 70°C - 60°C
∆T = 10°C
Step 2: Plug the values into the formula and calculate:
Q = (mass) * (specific heat capacity) * (∆T)
Q = 100 g * 4.18 J/g°C * 10°C
Q = 4180 J
Therefore, you would need to supply 4180 joules of energy to raise the temperature of 100 grams of water from 60 degrees Celsius to 70 degrees Celsius.