Math

With s(t) measured in feet and t in seconds, the equation s(t)= -16t^2 + 32t expresses the height of a ball above the ground after t seconds if it were thrown upward with a velocity of 32 ft/sec.

(a) What is the maximum height of the ball?
(b) After how many seconds will the maximum height occur?

asked by Pao
  1. (b) recall that the vertex of a parabola is at t = -b/2a. In this case, that's 32/32 = 1.
    (a) just plug in t=1.

    posted by Steve
  2. (110)

    posted by lena

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