A solution was prepared using 1,00 liter of water, 59 g glucose, and 2,3 g NaCl. One liter of water weighs 1000 grams. The solution needs to be labeled in terms of % glucose and % sucrose.
%by mass = (mass solute/mass solution)*100 = ?
mass solution = 1000gH2O + 59g glucose + 2.3g NaCl.
% glucose = (59/1061.3)*100 = ?
% NaCl = (2.3/1061.3)*100 = ?
% H2O = (1000/1061.2)*100 = ?
% sucrose = 0%
If your prof is picky about the number of significant figures be sure to round the final percent number to the correct number of s.f.
To determine the percent of glucose and sucrose in the solution, we need to calculate the mass of glucose and sucrose and then express it as a percentage of the total mass of the solution.
Given:
Mass of water = 1000 grams
Mass of glucose = 59 grams
Mass of NaCl = 2.3 grams
First, let's calculate the total mass of the solution:
Total mass of solution = Mass of water + Mass of glucose + Mass of NaCl
Total mass of solution = 1000 grams + 59 grams + 2.3 grams
Total mass of solution = 1061.3 grams
Next, let's calculate the mass of sucrose. However, the problem statement does not provide any information about the presence of sucrose in the solution. Therefore, we cannot determine the percentage of sucrose in the solution without additional information.
However, we can calculate the percentage of glucose in the solution.
Percentage of glucose = (Mass of glucose / Total mass of solution) × 100
Percentage of glucose = (59 grams / 1061.3 grams) × 100
Percentage of glucose ≈ 5.56%
Therefore, we can label the solution as approximately 5.56% glucose. However, we cannot determine the percentage of sucrose without additional information.