A crate weighing 600. N is being pulled across the floor. You pull up and to the right on a rope which is attached to the crate. You exert a force of 155 N at an angle θ=29.0° above the horizontal.
Incomplete.
To find the horizontal and vertical components of the force exerted on the crate, we can use trigonometry. Let's break down the given information:
- The force magnitude you exert is 155 N.
- The angle θ is 29.0° above the horizontal.
First, let's find the horizontal component of the force (Fx). We can use the cosine function because the horizontal component is adjacent to the angle θ.
cos(θ) = adjacent / hypotenuse
cos(29.0°) = Fx / 155 N
Solving for Fx:
Fx = 155 N * cos(29.0°)
Next, let's find the vertical component of the force (Fy). We can use the sine function because the vertical component is opposite to the angle θ.
sin(θ) = opposite / hypotenuse
sin(29.0°) = Fy / 155 N
Solving for Fy:
Fy = 155 N * sin(29.0°)
Finally, we can calculate the values of Fx and Fy:
Fx = 155 N * cos(29.0°) = 134.1 N (rounded to one decimal place)
Fy = 155 N * sin(29.0°) = 75.7 N (rounded to one decimal place)
So, the horizontal component of the force is approximately 134.1 N and the vertical component is approximately 75.7 N.