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The molar enthalpy of solution for ammonium chloride is 14.8kJ/mol. What is the final temperature observed when 20.0g of ammonium chloride is added to 125mL water at 20.0'C?

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  1. mols NH4Cl = 20 g/53.5 = about 0.37 but you need to do this and all other calculations here more accurately.
    14.8 kJ/mol x 0.37 mol = 5.5 kJ = 5500 J.

    Then -5500 J = mass H2O x specific heat H2O x (Tfinal-Tinitial)
    Solve for Tf.

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  2. Ok thanks a lot for your help I understand it now :D

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  3. Can some help me with this question

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