# calcius

Determine whether the relation represents a function. If it is a function, state the domain and range.

{(-2, 1), (-1, -2), (0, -3), (1, -2), (3, 6)}

a. function
domain: {-2, -1, 0, 1, 3}
range: {1, -2, -3, 6}

b. function
domain: {1, -2, -3, 6}
range: {-2, -1, 0, 1, 3}

c. not a function

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1. If it only has one value of y for each value of x, it is a function.
That is the case here.
x has values -2 -1 0 1 3
y has values 1 -2 -3 6
So a is correct.
It does not matter that y is -2 twice, because it is at different x values.
if y were -2 and +2 at the same x, then it would be a problem and it would not be a function.

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posted by Damon

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