If there are 0.561 g of NaCl left in a beaker that originally contained 75.0 mL of saltwater, what must have been the molar concentration of the original solution? The molar mass of NaCl is 58.44 g/mol. Give your answer to 3 decimal places
mols NaCl left in the beaker (the same as mols in the original solution) = grams/molar mass = ?
Then M = mols/L
Well, it seems like we've got a salty situation here! To calculate the molar concentration, we need to first convert the mass of NaCl left in the beaker to moles.
Using the molar mass of NaCl, which is 58.44 g/mol, we can calculate the moles of NaCl remaining:
0.561 g NaCl * (1 mol NaCl / 58.44 g NaCl) = 0.0096 mol NaCl
Next, we need to figure out the volume of the original solution. Since we know that the solution originally contained 75.0 mL, we can convert this to liters:
75.0 mL * (1 L / 1000 mL) = 0.075 L
Finally, using the moles of NaCl (0.0096 mol) and the volume of the original solution (0.075 L), we can calculate the molar concentration:
0.0096 mol / 0.075 L = 0.128 M
So, the molar concentration of the original solution must have been 0.128 M. Now that's some salty chemistry for you!
To find the molar concentration of the original solution, we can use the formula:
Molarity (M) = Moles of solute / Volume of solution in liters
First, let's calculate the moles of NaCl left in the beaker:
Moles = Mass / Molar mass
Moles = 0.561 g / 58.44 g/mol
Moles ≈ 0.0096 mol
Next, we need to convert the volume of the original solution to liters:
Volume = 75.0 mL = 75.0 mL × (1 L / 1000 mL)
Volume = 0.075 L
Now, we can use these values to determine the molar concentration of the original solution:
Molarity = 0.0096 mol / 0.075 L
Molarity = 0.128 M
Therefore, the molar concentration of the original solution must have been approximately 0.128 M.
To find the molar concentration of the original solution, we need to determine the number of moles of NaCl in the remaining 0.561 g.
First, let's find the number of moles using the molar mass of NaCl:
moles = mass / molar mass
moles = 0.561 g / 58.44 g/mol
moles ≈ 0.00961 mol
Next, let's determine the volume of the original solution in liters since the molar concentration is given in mol/L:
volume = 75.0 mL * (1 L / 1000 mL)
volume = 0.075 L
Now that we have both the moles and volume, we can calculate the molar concentration:
molar concentration = moles / volume
molar concentration = 0.00961 mol / 0.075 L
molar concentration ≈ 0.128 M
Therefore, the molar concentration of the original solution is approximately 0.128 M.