If the methane contained in 3.50L of a saturated solution at 25 ∘C was extracted and placed under STP conditions, what volume would it occupy?

Solubility of methane is 1.3 millimolar

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  1. M = mols/L
    0.0013 M = mols/3.50L
    mols = 0.0013 mols/L x 3.50L = estimated 0.005 mols but you need to do that more accurately.
    Then substitute for n in PV = nRT with other conditions and solve for volume.

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