# chemistry

A room contains 47kg of air. How many kilowatt-hours of energy are necessary to heat the air in the house from 7∘C to 26∘C? The heat capacity of air is 1.03 J/g∘C

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1. q = mass air x specific heat air x (Tfinal-Tintial)
You know q, mass, Tf and Ti. You will need to look up the specific heat of air. Solve for q (in joules) needed.

Then 1 watt = 1 joule/second
Here is a site that will convert joules to kW-hr.
http://www.rapidtables.com/convert/energy/Joule_to_kWh.htm

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