# Algebra

1. Solve for the 101st term of the sequence whose 1st term is x-y and d=2x+y-3.
2. In the sequence 2, 6, 10, … , what term has a value of 106?
3. Solve for the 101st term of the sequence: 6-p, 4+p, 2+3p, 5p, … .

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1. In all 3 questions you are using the same formula

term(n) = a + (n-1)d

1. term(101) = x-y + 100(2x+y-3)
= x-y+200x + 100y - 300
= 201x + 100y - 300

2.
a=2 , d=4
2 + (n-1)(4) = 106
4n-4 = 104
4n = 108
n = 27
It is the 27th term

3. give this one a try yourself

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posted by Reiny
2. x2(4x-8)-12

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