# algebra

Jim has some nickels, dimes and quarters worth \$5.30. There are five times as many dimes as quarters, and six more nickels than dimes. How many of each kind of coin does he have?

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1. 5D = Q

D + 6 = N

.05N + .10D + .25Q = 5.30

Substitute terms.

.5(D+6) + .10D + .25(5D) = 5.30

Solve for D, then N and Q.

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posted by PsyDAG

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