# chemistry

A 21.8603 g sample of impure magnesium carbonate was heated to complete decomposition according to the equation
MgCO3(s) → MgO(s) + CO2(g).
After the reaction was complete, the solid residue (consisting of MgO and the original impurities) had a mass of 18.7358 g. Assuming that only the magnesium carbonate had decomposed, how much magnesium carbonate was present in the original sample?

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1. MgCO3(s) → MgO(s) + CO2(g)
So the loss in mass is due to the evolved CO2.
mass CO2 = 21.8603 - 18.7358 = ?
Convert mass CO2 into mass MgCO3 this way.
mass MgCO3 = mass CO2 x (molar mass MgCO3/molar mass CO2) = ?

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posted by DrBob222

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