You toss a tennis ball straight upward. At the moment it leaves your hand it is at a height of 1.5 m above the ground, and it is moving at a speed of 8.0 m/s.

(a) How much time does it take for the tennis ball to reach its maximum height?

(b) What is the maximum height above the ground that the tennis ball reaches?

(c) When the tennis ball is at a height of 2.4 m above the ground, what is its speed?

Am I supposed to use the free fall formula?

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  1. v = Vi - 9.81 t
    at top, v = 0
    t = 8 / 9.81

    (b) h = 1.5 + 8 t -(1/2)(9.81) t^2

    (c) at 2.4 m, new t

    2.4 - 1.5 = 8 t - 4.9 t^2
    then v = 8 - 9.81 t

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