Physics for Technology

I have been out of school 27 years; no Algebra or Trigonometry training: only remedial math.
This class is part of a Diploma program, no placement test required - I am out of my depth.
I had a tutor for an hour last Tues., with another appt. this Tues.
Yet, like I told my instructor; I am years too far behind.

I just need to know what are the correct formulas and steps to use for problems like these:

What is the momentum of a hammer of mass 0.8kg striking a nail at 5 m/s2?
So, p = m v
p = (0.8)(5 m/s)2
p = 20 kg-m/s2
Correct?
A nail stops the hammer in 0.08 seconds: what force is delivered to the nail?
Force is mass times gravity?
So, F = (0.8kg) (9.8 m/s2)
F = (0.8) (9.8)2
F = 76.832 N?
Am I on the right path?

asked by James
  1. What is the momentum of a hammer of mass 0.8kg striking a nail at 5 m/s2?
    So, p = m v
    p = (0.8)(5 m/s)
    p = 4 kg-m/s note velocity is meters/seconds, acceleration is m/s^2


    A nail stops the hammer in 0.08 seconds: what force is delivered to the nail?

    NEWTON #2 Force = rate of change of momentum (m a)
    F = p/t = 4 kg m/s / .08 s
    F = 50 N

    posted by Damon

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