How to get results and balance the following equation FeC2O4 + H2SO4 + K2C2O4 + H2O2
This is a redox equation.
Fe^2+ probably is oxidized to Fe^3+.
C2O4^- probably is reduced to CO2.
H2O2 probably is reduced to H2O
Here is everything you wanted to know about redox equations.
http://www.chemteam.info/Redox/Redox.html
To balance the equation FeC2O4 + H2SO4 + K2C2O4 + H2O2, we need to ensure that the number of atoms of each element is the same on both sides of the equation. Here's how you can balance it step-by-step:
1. Start by balancing any complex ions or polyatomic ions that appear on both sides of the equation. In this case, the oxalate ions (C2O4) appear on both sides.
FeC2O4 + H2SO4 + K2C2O4 + H2O2
2. Count the number of oxalate ions on each side of the equation. On the reactant side, there is one FeC2O4 molecule, one K2C2O4 molecule, and zero on the product side.
FeC2O4 + H2SO4 + K2C2O4 + H2O2
3. We need to balance the number of oxalate ions. To do this, we can add a coefficient in front of the compound that contains oxalate ions. In this case, we need to add a coefficient of 2 in front of K2C2O4 to balance the equation.
FeC2O4 + H2SO4 + 2K2C2O4 + H2O2
4. Now let's balance the sulfur (S) atoms. On the reactant side, there is one sulfur atom in H2SO4, and on the product side, there is zero. To balance, add a coefficient of 2 in front of H2SO4.
FeC2O4 + 2H2SO4 + 2K2C2O4 + H2O2
5. Next, balance the hydrogen (H) atoms. On the reactant side, there are four hydrogen atoms in H2SO4, and on the product side, there are four hydrogen atoms in H2O2. The equation is already balanced in this regard.
FeC2O4 + 2H2SO4 + 2K2C2O4 + H2O2
6. Finally, balance the oxygen (O) atoms. On the reactant side, there are ten oxygen atoms: two in FeC2O4, eight in H2SO4. On the product side, there are fourteen oxygen atoms: four in H2O2 and ten in K2C2O4. In order to balance the equation, add a coefficient of 4 in front of FeC2O4.
4FeC2O4 + 2H2SO4 + 2K2C2O4 + H2O2
Now the equation is balanced:
4FeC2O4 + 2H2SO4 + 2K2C2O4 + H2O2.