How do I get the write out the problem for : The sample space is orange, purple and white. If P(orange)=2/5 and P(purple)=3/10, what is P(white)?
I have written 2/5.3/10=6/15 2/5
Step 1. Get common denominator (10 in this case)
2/5 is the same as 4/10.
orange is now 4/10 and purple is 3/10 and white is x/10.
2. Find x (xis white)
3. 10/10 - (3/10 + 4/10)
4. 10/10 - 7/10 = 3/10
3/10 is the answer
3/10
To calculate the probability of an event, you need to divide the number of favorable outcomes by the total number of possible outcomes. In this case, we are given the probabilities of orange and purple, and we need to find the probability of white.
Let's assign variables for the probabilities:
P(orange) = 2/5
P(purple) = 3/10
To find the probability of white, we need to consider that the sum of the probabilities of all the possible outcomes must equal 1. So, we can start by adding the given probabilities:
2/5 + 3/10
To add these fractions, we need to have a common denominator. In this case, the least common multiple of 5 and 10 is 10. So, we need to convert the fractions to have a denominator of 10:
(2/5) * (2/2) = 4/10
(3/10)
Now that we have a common denominator, we can add the fractions:
4/10 + 3/10 = 7/10
Therefore, the probability of white, P(white), is equal to 7/10.
To determine the probability of the event "white," we need to know the probabilities of all possible outcomes (orange, purple, and white) from the sample space.
Given that P(orange) = 2/5 and P(purple) = 3/10, we can calculate the remaining probability as follows:
1. Start by subtracting the probabilities of orange and purple from 1, since the sum of all probabilities in a sample space must equal 1.
1 - (2/5 + 3/10) = 1 - (4/10 + 3/10) = 1 - 7/10 = 3/10
Therefore, P(white) = 3/10.