a long spring is stretched by 2cm. P.E is u if the spring is stretched by 10cm, the P.E is stored in it will be
(A).U/25(B).U/5(C).5U(D).25U
(A).25^1/2cm(B).25cm(C).8.3cm(D).75cm
25
To calculate the potential energy (PE) stored in a spring, we can use the formula:
PE = (1/2) * k * x^2
where PE is the potential energy stored in the spring, k is the spring constant (a measure of stiffness of the spring), and x is the displacement (stretch or compression) of the spring from its equilibrium position.
Given that the spring is stretched by 2 cm and the potential energy stored is u, we can use this information to find the value of k. Let's consider this calculation:
u = (1/2) * k * (2 cm)^2
u = k * (1/2) * (2 cm)^2
u = k * (1/2) * 4 cm^2
u = 2k cm^2
Now, we can calculate the potential energy (PE) when the spring is stretched by 10 cm. Using the value of k that we just obtained, let's compute PE:
PE = (1/2) * k * (10 cm)^2
PE = (1/2) * 2k * 100 cm^2
PE = k * 100 cm^2
Therefore, the potential energy stored in the spring when it is stretched by 10 cm will be 100 times the initial potential energy (u) when the spring was stretched by 2 cm.