If the length of a rectangular is three feet longer than the width and the perimeter is 62 feet, what is the width?
x=width
x+3=length
(x)+(x+3)+(x)+(x+3)=62
solve for x
x = 14 ft
width --- x ft
length --- x+3 ft
2x + 2(x+3) = 62
take over.
To find the width of the rectangle, we can use the formula for the perimeter of a rectangle, which is 2 times the length plus 2 times the width.
Let's assume the width of the rectangle is w feet. According to the problem, the length of the rectangle is three feet longer than the width, so the length would be w + 3 feet.
The formula for the perimeter can be written as:
Perimeter = 2(length) + 2(width)
Plugging in the given values, we have:
62 = 2(w + 3) + 2w
Now we can simplify and solve for w:
62 = 2w + 6 + 2w
62 - 6 = 4w
56 = 4w
Dividing both sides by 4, we get:
w = 14
So, the width of the rectangle is 14 feet.