alg 2

what is the foci of the ellipse

(x+5)^2/4+(y-1)^2/16=1

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  1. it's just like the last problem. however, this ellipse is vertical because b > a. the foci are at (h, k +/- c).

    h = -5
    k = 1
    a = 4
    b = 2

    4^2 = 2^2 + c^2
    16 = 4 + c^2
    12 = c^2
    2 x the square root of 3 = c

    foci = (-5, 1 +/- (2 x the square root of 3))

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