A HPHS012 student throws a water balloon vertically downward from the top of a building. The balloon leaves the thrower’s hand with a speed of 6.00m/s. Air resistance may be ignored, so the water balloon is in free fall after it leaves the thrower’s hand.
What is the question?
To determine the behavior of the water balloon as it falls, we can use the principles of kinematics. In this case, we are given the initial velocity of the water balloon as it leaves the thrower's hand (6.00 m/s). We can assume that the positive direction is downward since the balloon is thrown vertically downward.
Now, let's answer some possible questions related to the behavior of the water balloon:
1. How long does it take for the water balloon to hit the ground?
To find the time it takes for the balloon to hit the ground, we can use the equation of motion:
s = ut + (1/2)gt^2
where:
s = displacement (in this case, the height of the building)
u = initial velocity (6.00 m/s)
t = time taken
g = acceleration due to gravity (approximately 9.8 m/s^2)
Since the balloon is thrown vertically downward, the displacement is negative because it is moving in the opposite direction of positive displacement (upwards). Let's assume the height of the building is h.
s = -h
u = -6.00 m/s
g = 9.8 m/s^2
Plugging in these values, the equation becomes:
-h = -6.00t - (1/2)(9.8)t^2
Solving this equation will give us the time it takes for the water balloon to hit the ground.
2. What is the final velocity of the water balloon when it hits the ground?
The final velocity of the water balloon when it hits the ground can be calculated using the equation:
v = u + gt
where:
v = final velocity
u = initial velocity (6.00 m/s)
g = acceleration due to gravity (approximately 9.8 m/s^2)
t = time taken calculated from the previous equation
Plugging in the known values, we can calculate the final velocity.
3. What is the maximum height reached by the water balloon?
To find the maximum height reached by the water balloon, we need to determine the time it takes for the balloon to reach its highest point. At this point, the velocity of the balloon will be zero.
v = u + gt
Plugging in the known values:
0 = -6.00 + 9.8t
Solving this equation will give us the time it takes to reach the highest point. We can then substitute this time into the equation s = ut + (1/2)gt^2 to find the maximum height.
Remember, all these calculations assume that air resistance can be ignored.