A conductor of length 0.5m moves in a uniform magnetic field of flux density 2 wbm. at a uniform velocity of 40m/s. Calculate the induced EMF under the following conditions:
(1) the conductor moves at right angle to the magnetic field
(2) the conductor moves at an angle of 30 degrees to the direction of the field
To calculate the induced EMF (electromotive force), you can use the following formula:
EMF = B * v * L * sin(θ),
where:
- EMF is the induced electromotive force,
- B is the magnetic field flux density,
- v is the velocity of the conductor,
- L is the length of the conductor, and
- θ is the angle between the direction of motion and the magnetic field.
Let's calculate the induced EMF under each given condition:
(1) When the conductor moves at a right angle to the magnetic field (θ = 90 degrees):
EMF = 2 Wb/m² * 40 m/s * 0.5 m * sin(90 degrees)
= 2 * 40 * 0.5 * 1
= 40 V
Thus, the induced EMF is 40 Volts.
(2) When the conductor moves at an angle of 30 degrees to the direction of the field (θ = 30 degrees):
EMF = 2 Wb/m² * 40 m/s * 0.5 m * sin(30 degrees)
= 2 * 40 * 0.5 * 0.5
= 20 V
Therefore, the induced EMF is 20 Volts.