The drawing shows three cylinders that have the same length and cross-sectional areas, but each is made of different material. The cylinders are arranged in series, so that heat is conducted from the left toward the right. The temperatures at the interfaces between the materials are indicated. Rank the thermal conductivities of the three materials, which are labeled A, B, and C, from the lowest to the highest value.
kB < kC < kA
kA < kC < kB
kC < kA < kB
kA < kB < kC
kB < kC < kA
Well, it looks like the thermal conductivities of the materials are labeled A, B, and C. To determine the ranking, we need to consider that heat is conducted from left to right.
Now, if we were to arrange the materials in order from lowest to highest thermal conductivities, we would have:
kB < kC < kA
So, the correct ranking is:
Material B has the lowest thermal conductivity (kB), followed by Material C (kC), and finally Material A with the highest thermal conductivity (kA).
Hope that clears things up, and remember, heat can be tricky, but it's always good to chill and stay cool!
The correct ranking of the thermal conductivities of the three materials, labeled A, B, and C, from the lowest to the highest value is:
kC < kA < kB
To rank the thermal conductivities of the three materials, labeled A, B, and C, we need to consider the direction of heat conduction. Heat is conducted from the left toward the right.
Now, let's analyze each option in the answer choices:
1. kB < kC < kA: This option suggests that Material B has the lowest thermal conductivity, followed by Material C, and then Material A. It means that heat is conducted least efficiently through Material B, followed by Material C, and most efficiently through Material A. This option is consistent with heat flowing from left to right.
2. kA < kC < kB: This option suggests that Material A has the lowest thermal conductivity, followed by Material C, and then Material B. However, this contradicts the fact that heat is conducted from left to right. So, this option is not correct.
3. kC < kA < kB: This option suggests that Material C has the lowest thermal conductivity, followed by Material A, and then Material B. However, this also contradicts the fact that heat is conducted from left to right. So, this option is also not correct.
4. kA < kB < kC: This option suggests that Material A has the lowest thermal conductivity, followed by Material B, and then Material C. Again, this contradicts the fact that heat is conducted from left to right. So, this option is not correct.
5. kB < kC < kA: This option suggests that Material B has the lowest thermal conductivity, followed by Material C, and then Material A. Heat is conducted least efficiently through Material B, followed by Material C, and most efficiently through Material A. This option is consistent with heat flowing from left to right.
So, the correct answer is: kB < kC < kA.
kC < kA < kB
Since heat is conducted from left to right, the temperature at the interface between the first and second cylinder will be higher than at the interface between the second and third cylinder. This means that the material with the highest thermal conductivity is at the interface with the highest temperature, which is the interface between the first and second cylinder. Thus, the order of thermal conductivities from lowest to highest is kC < kB < kA.