m1(x)=m2(3-x) (for x)
Hmm, well I see you have an equation there, but it seems like you might be missing some information. Are m1 and m2 meant to be the same? Because if they are, we have a little equation dance going on: m1 times x equals m2 times (3 minus x). It's like they're partners in crime, constantly changing places. Maybe they're trying to pull off the ultimate prank on the variable x. So, what exactly would you like to know about this equation?
To find the value of x that satisfies the equation m1(x) = m2(3-x), we can start by setting the two functions equal to each other.
m1(x) = m2(3 - x)
Next, we need to determine what values of x will make this equation true. To do this, we can compare the two functions m1(x) and m2(3 - x).
If m1(x) = m2(3 - x), it means that the two functions have the same output for all values of x.
To find x, we can equate the inputs of the two functions:
x = 3 - x
Simplifying this equation, we can combine like terms:
2x = 3
Finally, we can solve for x by dividing both sides of the equation by 2:
x = 3/2 or x = 1.5
Therefore, the values of x that satisfy the equation m1(x) = m2(3 - x) are x = 3/2 or x = 1.5.
To find the value of x that satisfies the equation m1(x) = m2(3-x), follow these steps:
Step 1: Expand the equation.
Start by expanding m1(x) and m2(3-x) to get rid of the parentheses. Let's assume m1 and m2 are constants:
m1(x) = m2(3 - x)
m1(x) = 3m2 - m2x
Step 2: Isolate the variable.
Move all the terms containing x to one side of the equation and all the constant terms to the other side:
m1(x) + m2x = 3m2
Step 3: Combine like terms.
Combine the terms containing x:
(x)(m1 + m2) = 3m2
Step 4: Solve for x.
Divide both sides of the equation by (m1 + m2):
x = (3m2) / (m1 + m2)
So, x equals (3m2) divided by (m1 + m2).
this just algebra I
m1*x = m2*3 - m2*x
(m1+m2)x = 3m2
x = 3m2/(m1+m2)