how many ml of water are present in 250ml of a 15% by volume oguous hydrocloric acid solution?

15% w/v means 15 g solute in 100 mL solution.

[(x g solute)/250 mL] = 0.15
x g solute = 250 x 0.15 = 37.5g HCl

Therefore,
(37.5g HCl)/(mL HCl + mL H2O) = 0.15
Since mL HCl + mL H2O = 250, you can solve for mL H2O if you know the volume occupied by 37.5g HCl. There is no date in your problem to show that or to allow us to calcluate it.

Well, let's break it down. If the solution is 15% hydrochloric acid, then the remaining 85% must be water.

So, if we have 250 ml of a 15% solution, we can find out how much water is present by multiplying the volume by the percentage:

250 ml x 0.85 = 212.5 ml

So, there are approximately 212.5 ml of water in 250 ml of a 15% hydrochloric acid solution. And hey, that's quite a splash of H2O!

To find out how many milliliters (ml) of water are present in a 250ml solution of 15% by volume hydrochloric acid (HCl), we need to determine the amount of HCl in the solution and then subtract it from the total volume.

Step 1: Calculate the volume of HCl in the solution:
15% of 250ml = (15/100) * 250 = 37.5ml

Step 2: Subtract the volume of HCl from the total volume to find the volume of water:
250ml - 37.5ml = 212.5ml

Therefore, there are 212.5ml of water present in a 250ml solution of 15% by volume hydrochloric acid.

To find out how many milliliters (ml) of water are present in a 250ml solution of 15% by volume hydrochloric acid, we need to calculate the volume of hydrochloric acid and subtract it from the total volume of the solution.

Step 1: Calculate the volume of hydrochloric acid:
Since the solution is 15% hydrochloric acid by volume, it means that 15% of the total volume is hydrochloric acid. We can calculate it by multiplying the total volume (250ml) by 0.15 (15% as a decimal):
Volume of hydrochloric acid = 250ml * 0.15 = 37.5ml

Step 2: Calculate the volume of water:
To find the volume of water, subtract the volume of hydrochloric acid from the total volume of the solution:
Volume of water = Total volume - Volume of hydrochloric acid
Volume of water = 250ml - 37.5ml = 212.5ml

Therefore, there are 212.5ml of water present in 250ml of a 15% by volume hydrochloric acid solution.