The drug is a salt form while a molecular weight of 181.6G/mol. She needs a concentration of the stock solution of 100mM and she needs to make 1.2mL of the drug. How many grams will she need to weight out in order to make the stock solution?
This problem isn't clear to me at all. Is the drug a liquid? density is needed if we are to make 1.2 mL. How much is the stock solution to be diluted?
She needs to prepare a stock solution of Drug-A. The concentration of the stock solution she needs is 100mM and she needs to make 1.2mL solution of the drug A. The drug is in salt form weighing 181.6G/mol. What is the amount of G of drug-a will she have to make the stock solution?
I may have interpreted this all wrong but I think you want 1.2 mL of 100 mM solution. If that is true then
100 mM x 1.2 mL = ? mmols or ?/1000 = mols.
mols = grams/molar mass. You have molar mass and mols, solve for grams.
18.16mL of drug-a?
To determine the amount of grams needed to make the stock solution, we'll use the following formula:
Mass (in grams) = Concentration (in moles/L) × Volume (in liters) × Molecular Weight (in g/mol)
Step 1: Convert the concentration from millimoles (mM) to moles per liter (mol/L).
Concentration (in mol/L) = 100 mM ÷ 1000
Step 2: Convert the volume from milliliters (mL) to liters.
Volume (in L) = 1.2 mL ÷ 1000
Step 3: Calculate the mass.
Mass (in grams) = Concentration (in mol/L) × Volume (in L) × Molecular Weight (in g/mol)
Substituting the values:
Mass (in grams) = [(100 mM ÷ 1000) × (1.2 mL ÷ 1000)] × 181.6 g/mol
Simplifying the equation:
Mass (in grams) = (0.1 × 0.0012) × 181.6
Mass (in grams) = 0.21792 g
Therefore, she will need to weigh out 0.21792 grams of the drug to make the 100 mM stock solution.