Using the gas laws, calculate the new volume of methane gas at STP, which has escaped from a landfill and been captured at an initial pressure of 1.50atm, an initial volume of 30.0L and an initial temperature of 40.0C.
(P1V1/T1) = (P2V2/T2)
Whatever units you use for the left side use the same units for the right side.
I am only given P1V1T1 though...I am not given the other values..P2V2 and T2
Yes you are, STP means standard temperature and pressure. So P is 1 atm standard, T is 273 K standard and you are to calculate standard V.
To calculate the new volume of methane gas at STP (Standard Temperature and Pressure), we can use the combined gas law formula:
(P1 * V1) / (T1) = (P2 * V2) / (T2)
Where:
P1 = initial pressure of the gas
V1 = initial volume of the gas
T1 = initial temperature of the gas (in Kelvin)
P2 = final pressure of the gas (at STP, which is 1 atmosphere)
V2 = final volume of the gas (what we need to find)
T2 = final temperature of the gas (also at STP, which is 273.15 Kelvin)
Now let's solve for V2:
First, convert the initial temperature from Celsius to Kelvin:
T1 = 40.0 + 273.15 = 313.15 K
Next, plug in the given values into the formula:
(1.50 atm * 30.0 L) / (313.15 K) = (1.00 atm * V2) / (273.15 K)
Now, solve for V2:
V2 = (1.50 atm * 30.0 L * 273.15 K) / (313.15 K * 1.00 atm)
V2 = 34.94 L
Therefore, the new volume of methane gas at STP is approximately 34.94 L.