science

A body freely falling from a height h describes 11h/36 in the last second of its fall. Find the height h?

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asked by seshu
  1. the position falling from a height of h feet is

    y = h - 16t^2
    After t seconds, y=0, so
    h=16t^2

    So, we have

    (h-16t^2) - (h-16(t-1)^2) = 11h/36
    0 - (16t^2 - 16(t-1)^2) = 11(16t^2)/36
    32t-16 = 44/9 t^2
    11t^2 - 72t - 36 = 0
    t = 7.01

    So, h = 16t^2 = 786.24 ft

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    posted by Steve
  2. I may have messed up the sign change, so double check my math.

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    posted by Steve
  3. the equations of a motions for a body falling down freely under gravity

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