physics

A car is moving on a straight road due north with a uniform speed of 50km h^-1 when it turns left through 90°. It the speed remains unchanged after turning, the change in the velocity of the car in the turning process is :

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asked by jha
  1. Let the North be represented by Y axis.  The when the car turns left, it moves along the -ve x axis, towards West.

    Let

    Change in velocity is = \vec{v2}-\vec{v1}=-50\hat{i}-50\hat{j}\ kmph

    Magnitude of change in velocity=sqrt{50^2+50^2}=50\sqrt{2}

    Direction of the change in velocity = South west , 45 deg. from South towards West.

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