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Intergrate ¡ì sec^3(x) dx could anybody please check this answer. are the steps correct? thanks. = ¡ì sec x d tan x = sec x tan x  ¡ì tan x d sec x = sec x tan x  ¡ì sec x tan^2(x) dx = sec x tan x + ¡ì sec x dx  ¡ì
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help Please... Differential Equations Problems... please give the complete solution, so that i can understand how it is derived... tnx in advance, god Bless... Here are the problems : 1.) y dx + (2x+3y)dy = 0 2.) (2xy + y^(2) ) dx
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help Please... Differential Equations Problems... please give the complete solution, so that i can understand how it is derived... tnx in advance, god Bless... Here are the problems : 1.) y dx + (2x+3y)dy = 0 2.) (2xy + y^(2) ) dx
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How would you establish this identity: (1+sec(beta))/(sec(beta))=(sin^2(beta))/(1cos(beta)) on the right, sin^2 = 1cos^2, that factor to 1cos * `1+cos, then the denominator makes the entire right side 1+cosB which is 1+1/sec
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Combine the following rational expressions 1/2y530/8y^3125 Lcm:(2y5)(4y^2+10y+125) =1*4y^2+10y+25/(2y5)(4y^2+10y+25)30/(2y5)(4y^2+10y+25) =4y^210y+2530/(2y5)(4y^2+10y+25) =(4y^2+10y5)/(2y5)(4y^2+10y+25) Please correct
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