Calc please help

Find the derivative of f(x) (csc(2x^2+1)^4

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asked by Sarah
  1. just use the chain rule:

    f = u^4
    u = csc(v)
    v = 2x^2+1

    f' = 4u^3 u'
    u' = -csc(v) cot(v) v'
    v' = 4x

    So,

    f' = 4 (csc(2x^2+1)^3 * (-csc(2x^2+1)*cot(2x^2+1)) * (4x)
    = -16x csc^4(2x^2+1) cot(2x^2+1)

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    posted by Steve

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