Precalculus

A rectangle is inscribed in a circle of radius 2. Find a function that represents the area of the rectangle in terms of x.

I have
(x^2)(y^2)=4 Pythagorean Theorem
(y^2)=4-(x^2)
y=sqrt(4-(x^2))
A=bh or A=xy
A=2x*2sqrt(4-(x^2))

Is this correct or what am I doing wrong?

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asked by Clair
  1. the diagonal of the rectangle is a diameter of the circle. Since that is 4, if the rectangle has one side of length x, then the other side has length √(16-x^2)

    So, the area is x√(16-x^2)

    Well, that is not a choice, so if the side is 2x, rather than x, the area is

    (2x)√(16-4x^2)
    = 4x√(4-x^2)

    You are correct.

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    posted by Steve
  2. Thank you

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    posted by Clair

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