math

The sides of the triangle are on the of x+y+6=0, x+2y-4=0, 3x+y+2=0. Find the vertices of the triangle

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  1. Given three non-parallel lines.
    We are to find the vertices of a triangle formed by the intersection of the lines.

    The intersections are found by solving for the three systems of two equations at a time.

    For example:
    L1: x+y+6=0
    L2: x+2y-4=0
    Subtract L1 from L2 gives:
    y-10=0, this means that
    y=10
    Now substitute y=10 in equation L1 gives x+10+6=0
    x=-16.
    So (-16,10) is one of the vertices.

    Repeat the same for lines L2 & L3, and then L1 & L3 will give the two other vertices.

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