# Algebra

multiply
(n^3+8)(n-4)
can you give me an example on how to solve this please

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1. (x^3+3)(x-1)=x^4-x^3+3x-3
=x(x^3-x^2+3)-3
=x-3=0.....eqn1
=x^3-x^2+3=0...eqn2
From eqn2 using a calculator u get
X=-1.17,x=1.09,x=1.09
From eqn1 u get x=3. U get 4 answer for this algebra because x is raised to the power 4 i.e x^4 when u open ur bracket.

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posted by tope

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