calculate the volume of hydrogen produced from .025g of aluminum and sufficient HCl at 21 degrees Celsius and 755 torr according to the following reaction:

Al(s) + HCl(aq)--------- AlCl3 (aq) + H2(g)

Volume of H2________ml

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asked by amber
  1. 2Al + 6HCl ==> 2AlCl3 + 3H2
    mols Al = grams/molar mass
    Using the coefficients in the balanced equation, convert mols Al to mols H2.
    Then use PV = nRT and convert mols H2 to L at the conditions listed. Change L to mL.

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