pre cal

f(x) = two divided by quantity x squared minus two x minus three

Graph

A coordinate axis scaled by one.

Domain and Range : _____________________

x and y Intercept(s) : _____________________

Horizontal Asymptote(s) : ___________________

Vertical Asymptote(s) : ____________________

f(x) = quantity x squared plus x minus two divided by quantity x squared minus three x minus four

Graph
A coordinate axis scaled by one.

Domain and Range : _____________________

x and y Intercept(s) : _____________________

Horizontal Asymptote(s) : ___________________

Vertical Asymptote(s): ___________________

  1. 👍 0
  2. 👎 0
  3. 👁 959
asked by alex
  1. Good grief. How about some math, instead of the noisy words? I'll do one.

    f(x) = (x^2+x-2)/(x^2-3x-4)

    All polynomials have domain of all reals.
    Rationals have a domain of all reals except where the denominator is zero. Since

    f(x) = (x+2)(x-1) / (x-4)(x+1)

    The domain is all reals except x = -1 or 4

    x-intercepts (where y=0) are at -2 and 1
    y-intercept (where x=0) is at 1/2

    Vertical asymptotes are where the denominator is zero and the numerator is not: x = -1 and 4. Note that those are where f(x) is not defined.

    Horizontal asymptotes are where x is very large. In that case, f(x) is approximately

    (x^2)/(x^2) = 1

    Note that it is possible for the graph to cross the horizontal asymptotes, but at the extreme ends of the x-axis, the curve approaches them.

    1. 👍 0
    2. 👎 0
    posted by Steve
  2. 1. F(x) = 2/(x^2-2x-3)
    C = -3 = 1*(-3). 1+(-3) = -2 = B.
    F(x) = 2/(x+1)(x-3)

    x+1 = 0
    X = -1, Denominator = 0.

    x-3 = 0
    X = 3, Denominator = 0.

    Domain = All real values of x except -1,
    and 3.

    Y-int. = 2/(0+1)(0-3) = 2/-3 = -2/3

    No x-intercept, because the numerator is
    constant and the fraction cannot be set
    to 0.

    2. F(x) = (x^2+x-2)/(x^2-3x-4)=
    (x-1)(x+2)/(x+1)(x-4).
    x+1 = 0
    X = -1, Denominator = 0.

    x-4 = 0
    X = 4, Denominator = 0.

    Domain = All real numbers except -1 and
    4.

    Y-int. = (0-1)(0+2)/(0+1)(0-4) = -2/-4 =
    1/2.

    Y = (x-1)(x+2)/(x+1)(x-4) = 0
    (x-1)(x+2) = 0

    x-1 = 0
    X = 1 = x-int.

    x+2 = 0
    X = -2 = x-int.

    X-Intercepts = 1, and -2.

    1. 👍 0
    2. 👎 0
    posted by Henry
  3. Thanks!

    1. 👍 0
    2. 👎 0

Respond to this Question

First Name

Your Response

Similar Questions

  1. Quick calc question

    Which of the following definite integrals could be used to calculate the total area bounded by the graph of y = 1 – x2 and the x-axis? the integral from 0 to 1 of the quantity 1 minus x squared, dx plus the integral from 1 to 2

    asked by Ella on February 23, 2016
  2. Quick calc question

    Which of the following definite integrals could be used to calculate the total area bounded by the graph of y = 1 – x2 and the x-axis? the integral from 0 to 1 of the quantity 1 minus x squared, dx plus the integral from 1 to 2

    asked by Mel on February 12, 2016
  3. Calculus

    Which of the following definite integrals could be used to calculate the total area bounded by the graph of y = 1 – x2 and the x-axis? the integral from 0 to 1 of the quantity 1 minus x squared, dx plus the integral from 1 to 2

    asked by Ella on February 18, 2016
  4. Quick calc question

    Which of the following definite integrals could be used to calculate the total area bounded by the graph of y = 1 – x2 and the x-axis? the integral from 0 to 1 of the quantity 1 minus x squared, dx plus the integral from 1 to 2

    asked by Ella on February 17, 2016
  5. Math

    What is the simplified form of The quantity x to the fourth power minus 81 divided by the quantity x plus 3 ? A. x cubed minus 3 times x squared plus 9 times x minus 27 B. the quantity x squared plus 9 times the quantity x squared

    asked by lexie on May 18, 2018
  1. math

    Simplify completely quantity 6 x squared minus 54 plus 84 over quantity 8 x squared minus 40 x plus 48 divided by quantity x squared plus x minus 56 over quantity 2 x squared plus 12 x minus 32

    asked by angela on November 25, 2014
  2. Calculus AB

    Which of the following functions is continuous at x = 3? (5 points) Select one: a. f of x equals the quotient of the quantity x squared minus 9 and the quantity x plus 3 b. f of x equals the quotient of the quantity x squared

    asked by Mayur on December 29, 2017
  3. Calculus

    Which of the following integrals cannot be evaluated using a simple substitution? the integral of the square root of the quantity x minus 1, dx the integral of the quotient of 1 and the square root of the quantity 1 minus x

    asked by Jana on February 19, 2016
  4. Calculus

    Which of the following integrals cannot be evaluated using a simple substitution? the integral of the square root of the quantity x minus 1, dx the integral of the quotient of 1 and the square root of the quantity 1 minus x

    asked by Ella on February 18, 2016
  5. Quick calc question

    Which of the following integrals cannot be evaluated using a simple substitution? the integral of the square root of the quantity x minus 1, dx the integral of the quotient of 1 and the square root of the quantity 1 minus x

    asked by Ella on February 17, 2016

More Similar Questions