pre cal

f(x) = two divided by quantity x squared minus two x minus three

Graph

A coordinate axis scaled by one.

Domain and Range : _____________________

x and y Intercept(s) : _____________________

Horizontal Asymptote(s) : ___________________

Vertical Asymptote(s) : ____________________

f(x) = quantity x squared plus x minus two divided by quantity x squared minus three x minus four

Graph
A coordinate axis scaled by one.

Domain and Range : _____________________

x and y Intercept(s) : _____________________

Horizontal Asymptote(s) : ___________________

Vertical Asymptote(s): ___________________

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asked by alex

  1. Good grief. How about some math, instead of the noisy words? I'll do one.

    f(x) = (x^2+x-2)/(x^2-3x-4)

    All polynomials have domain of all reals.
    Rationals have a domain of all reals except where the denominator is zero. Since

    f(x) = (x+2)(x-1) / (x-4)(x+1)

    The domain is all reals except x = -1 or 4

    x-intercepts (where y=0) are at -2 and 1
    y-intercept (where x=0) is at 1/2

    Vertical asymptotes are where the denominator is zero and the numerator is not: x = -1 and 4. Note that those are where f(x) is not defined.

    Horizontal asymptotes are where x is very large. In that case, f(x) is approximately

    (x^2)/(x^2) = 1

    Note that it is possible for the graph to cross the horizontal asymptotes, but at the extreme ends of the x-axis, the curve approaches them.

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    posted by Steve

  2. 1. F(x) = 2/(x^2-2x-3)
    C = -3 = 1*(-3). 1+(-3) = -2 = B.
    F(x) = 2/(x+1)(x-3)

    x+1 = 0
    X = -1, Denominator = 0.

    x-3 = 0
    X = 3, Denominator = 0.

    Domain = All real values of x except -1,
    and 3.

    Y-int. = 2/(0+1)(0-3) = 2/-3 = -2/3

    No x-intercept, because the numerator is
    constant and the fraction cannot be set
    to 0.

    2. F(x) = (x^2+x-2)/(x^2-3x-4)=
    (x-1)(x+2)/(x+1)(x-4).
    x+1 = 0
    X = -1, Denominator = 0.

    x-4 = 0
    X = 4, Denominator = 0.

    Domain = All real numbers except -1 and
    4.

    Y-int. = (0-1)(0+2)/(0+1)(0-4) = -2/-4 =
    1/2.

    Y = (x-1)(x+2)/(x+1)(x-4) = 0
    (x-1)(x+2) = 0

    x-1 = 0
    X = 1 = x-int.

    x+2 = 0
    X = -2 = x-int.

    X-Intercepts = 1, and -2.

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    posted by Henry

  3. Thanks!

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    posted by Jorgeeee

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