Choose the point on the terminal side of -45°
Cos(-45) = 1/sqrt2 = X/r
x^2 + y^2 = r^2
1^2 + y^2 = ((2)^1/2)2
1 + y^2 = 2
y^2 = 2-1 = 1
Y = sqrt1 = +-1.
Y = -1(Q4).
P(x,y) = (1,-1).
thats not one of the answer choices
(1/sqrt2,-1/sqrt2).
sqrt = Square root of 2.
To find a point on the terminal side of -45°, we'll use the coordinate system.
Step 1: Draw the coordinate plane.
Start by drawing a set of perpendicular axes. The horizontal axis is called the x-axis and the vertical axis is called the y-axis.
Step 2: Plot the initial point.
Since -45° is a negative angle, we will rotate clockwise from the positive x-axis. To do this, start at the positive x-axis (to the right of the origin) and rotate 45° clockwise.
Step 3: Find the coordinates of the point.
We need to determine the coordinates of the point where our rotated line intersects with any of the axes.
When we rotate 45° clockwise from the positive x-axis, we end up in the fourth quadrant. In the fourth quadrant, the x-coordinate (the value on the x-axis) is positive, and the y-coordinate (the value on the y-axis) is negative.
Since the point is on the terminal side, it lies on the unit circle with radius 1. The coordinates of the point will be given by (x, y), where x and y represent the distances from the origin along the x and y axes, respectively.
In the fourth quadrant, x is positive (to the right of the origin) and y is negative (below the origin). Hence, the coordinates of the point on the terminal side of -45° are (√2/2, -√2/2).
Keep in mind that these coordinates represent one of many possible points on the terminal side of -45°, as angles in standard position have infinite equivalent angles.