A quantity of 12.75 mL of a KOH solution is needed to neutralize 0.5109 g of KHP. What is the concentration (in molarity) of the KOH solution?
KHP + KOH ==> K2P + H2O
moles KHP = gams/molar mass.
Using the coefficients in the balanced equation, convert mols KHP to mols KOH.
M KOH = mols KOH/L KOH
To find the concentration (in molarity) of the KOH solution, we need to use the formula:
Molarity (M) = moles of solute / volume of solution (in liters)
First, we need to calculate the moles of KHP (solute). We can use the molar mass of KHP to convert the given mass to moles.
Step 1: Calculate moles of KHP
Molar mass of KHP (C8H5KO4) = 204.22 g/mol
Mass of KHP given = 0.5109 g
moles of KHP = Mass / Molar mass
moles of KHP = 0.5109 g / 204.22 g/mol
Now we have the moles of KHP.
Step 2: Convert mL of KOH solution to liters
Given volume of KOH solution = 12.75 mL
To calculate the volume in liters, divide by 1000 (since there are 1000 mL in 1 L):
Volume of KOH solution (in liters) = 12.75 mL / 1000 mL/L
Now we have the volume in liters.
Step 3: Calculate the concentration (molarity) of the KOH solution
Molarity (M) = moles of solute / volume of solution (in liters)
Molarity (KOH solution) = moles of KHP / volume of KOH solution (in liters)
Substituting the values we calculated:
Molarity (KOH solution) = moles of KHP / volume of KOH solution (in liters)
Molarity (KOH solution) = (0.5109 g / 204.22 g/mol) / (12.75 mL / 1000 mL/L)
Now we can calculate the concentration (in molarity) of the KOH solution.